javaExecutor线程池案例
javaExecutor线程池案例
第一个例子:基础案例 自动控制线程的数量,且每个线程没有返回值,不能做最后的整合处理
第二个例子:进阶案例 固定线程的数量,每个线程有返回值,在左右线程结束后,将返回值累加
基础案例
import java.util.concurrent.Executors;
import java.util.concurrent.ThreadPoolExecutor;
/**
* 执行服务器
*/
public class Server {
//线程池
private ThreadPoolExecutor executor;
public Server(){
// 构造时 新建一个进程池
executor=(ThreadPoolExecutor)Executors.newCachedThreadPool();
//executor=(ThreadPoolExecutor)Executors.newFixedThreadPool(5);
}
//向线程池提交任务
public void submitTask(Task task){
System.out.printf("Server: A new task has arrived\n");
// 重点: 执行任务
executor.execute(task); //执行 无返回值
System.out.printf("Server: Pool Size: %d\n",executor.getPoolSize());
System.out.printf("Server: Active Count: %d\n",executor.getActiveCount());
System.out.printf("Server: Completed Tasks: %d\n",executor.getCompletedTaskCount());
}
public void endServer() {
executor.shutdown();
}
}
import java.util.Date;
import java.util.concurrent.TimeUnit;
/**
* 这里继承了 Runnable 接口,需要实现 void run 函数,这就是要执行的函数了
*/
public class Task implements Runnable {
private String name;
public Task(String name){
this.name=name;
}
public void run() {
try {
Long duration=(long)(Math.random()*1000);
System.out.printf("%s:修改文本 Task %s: Doing a task during %d seconds\n",Thread.currentThread().getName(),name,duration);
Thread.sleep(duration);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.printf("%s: Task %s: Finished on: %s\n",Thread.currentThread().getName(),name,new Date());
}
}
public class Main {
// 这个例子 由框架自动控制线程的数量,且每个线程没有返回值
public static void main(String[] args) throws InterruptedException {
// 创建一个执行服务器(进程池)
Server server=new Server();
// 创建100个任务,并发给执行器,等待完成
for (int i=0; i<100; i++){
Task task=new Task("Task "+i);
Thread.sleep(10);
// 提交到服务器执行
server.submitTask(task);
}
server.endServer();
}
}
进阶案例
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
import java.util.concurrent.ThreadPoolExecutor;
public class SumTest {
public static void main(String[] args) {
// 新建线程池
// 这里通过参数控制只能有4个线程,通常是CPU核心数或2倍
ThreadPoolExecutor executor=(ThreadPoolExecutor)Executors.newFixedThreadPool(4);
// 用来接收线程返回的结果
// Future是用来接受返回值的
List<Future<Integer>> resultList=new ArrayList<>();
//统计1-1000总和,分成10个任务计算,提交任务
for (int i=0; i<10; i++){
SumTask calculator=new SumTask(i*100+1, (i+1)*100);
// 提交任务
Future<Integer> result=executor.submit(calculator);
// 将结果放到数组中,这里还没结果,放进来的是引用
resultList.add(result);
}
// 每隔50毫秒,轮询等待10个任务结束
do {
System.out.printf("Main: 已经完成多少个任务: %d\n",executor.getCompletedTaskCount());
for (int i=0; i<resultList.size(); i++) {
Future<Integer> result=resultList.get(i);
System.out.printf("Main: Task %d: %s\n",i,result.isDone());
}
try {
Thread.sleep(50);
} catch (InterruptedException e) {
e.printStackTrace();
}
} while (executor.getCompletedTaskCount()<resultList.size());
// 所有任务都已经结束了,综合计算结果
int total = 0;
for (int i=0; i<resultList.size(); i++) {
Future<Integer> result=resultList.get(i);
Integer sum=null;
try {
sum=result.get();
total = total + sum;
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
}
}
System.out.printf("1-1000的总和:" + total);
// 关闭线程池
executor.shutdown();
}
}
import java.util.Random;
import java.util.concurrent.Callable;
public class SumTask implements Callable<Integer> {
//定义每个线程计算的区间
private int startNumber;
private int endNumber;
public SumTask(int startNumber, int endNumber){
this.startNumber=startNumber;
this.endNumber=endNumber;
}
@Override
public Integer call() throws Exception {
int sum = 0;
for(int i=startNumber; i<=endNumber; i++)
{
sum = sum + i;
}
Thread.sleep(new Random().nextInt(1000));
System.out.printf("%s: %d\n",Thread.currentThread().getName(),sum);
return sum;
}
}